EmbDev.net

Forum: µC & Digital Electronics The use of the diode in this circuit


von Alex (Guest)


Attached files:

Rate this post
useful
not useful
So basically this is a circuit with 2 diodes and it represents a NOT 
Circuit.
But I don't understand the use of the Diode 2 (D2) here . Even without 
it the circuit represents still a NOT Circuit  .

: Moved by Moderator
von MaWin (Guest)


Rate this post
useful
not useful
Without it, if T2 urns on and directs the current to T4, it may not pull 
down the base , and in effect the voltage between its emitter and base, 
of T3 low enough to turn it off.
UBE(T2)+UBE(T4) must be < UCE(T4)+UBE(T4) and may not be the case.
But UBE(T2)+UBE(T4) < UCE(T4)+Uf(D2)+UBE(T4) cetainly holds.

von Alex (Guest)


Attached files:

Rate this post
useful
not useful
I'm not sure that I understand what you said . I'm kinda lost with the 
UBE UCE and UF symbols because I'm not familiar with them.
Have a look at the screenshots that I made with/without Diode and tell 
me what I'm doing wrong .
Plus I'd like to know what's UBE UCE and UF with the use of the voltage 
shown in my screenshots . That will be great to understand their 
meanings.

von Alex (Guest)


Rate this post
useful
not useful
As you can see in the screenshots . They both lead me to the same 
result. That's why I got confused

von MaWin (Guest)


Rate this post
useful
not useful
Alex wrote:
> They both lead me to the same
> result.

Why do you write 0V an the first output an 0.2V on the second ?

Why is Uf just 0.2V ?

Use realistic UBE, UCE and Uf values, for instance 0.7 0.2 and 0.7V or 
from a transistor data sheet or use LTSpice.

The input transistor also has wrong 0.7V on base. It mainly works like 2 
diodes, either directing the current thru the 4k7 resistor into the base 
of the T2 or into te input.

I made a mistake in the formuals

UBE(T2)+UBE(T4) must be < UCE(T4)+UBE(T3) and this will not be the case.
But UBE(T2)+UBE(T4) < UCE(T4)+Uf(D2)+UBE(T3) cetainly holds

von foobar (Guest)


Rate this post
useful
not useful
> They both lead me to the same result.

Except that in the right diagramm T3 and T4 are both on and you have a 
short.  In the left, the 0.2V is not enough for the diode to conduct[1] 
and no current flows through T3.


[1] especially as the output is also 0.2V and not 0 (the 
collector-emitter voltage of T4) and hence the voltage across the diode 
is ~0V.

von Alex (Guest)


Rate this post
useful
not useful
>Except that in the right diagramm T3 and T4 are both on and you have a
>short.  In the left, the 0.2V is not enough for the diode to conduct[1]
>and no current flows through T3.

So the diode D2 function would be on this case : Preventing a short 
circuit ?

von MaWin (Guest)


Rate this post
useful
not useful
Alex wrote:
> So the diode D2 function would be on this case : Preventing a short
> circuit ?

Yes, or in other words: allow the output circuit to work as intended.

Please log in before posting. Registration is free and takes only a minute.
Existing account
Do you have a Google/GoogleMail account? No registration required!
Log in with Google account
No account? Register here.