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i need help in my project which is a counter that counter up or down fron 0 to 20 i alraedy did my counter code and its working will in active HDL but know i need to show the numbers in 7segment in nexys 3 fpga board i have the codes of the segment but i have a problem when i call the module of segment , it is giving me an error in active HDL can you please tell me what is the error i am attaching my code and also writing it here this is my current code :
module main #(parameter N=7) ( input switch, input button, input fastclk, output [3:0] enable, output reg[6:0] out ); wire[N:0]count; wire slowclk; clock c1(fastclk,slowclk); Updown u1(switch,button,slowclk,count); segment s1([3:0]count,[7:4]count,fastclk,enable,out); endmodule module clock(fastclk,slowclk); //clock code input fastclk; output wire slowclk; reg[25:0]period_count = 0; always @(posedge fastclk) begin period_count <= period_count + 1; end assign slowclk = period_count[25]; endmodule module Updown // UpDown Counter #(parameter N=7) ( input switch, input button, input clk, output reg [N:0]count=8'd0, ); always @(posedge clk) begin if(switch == 1 && button == 1) // Countup from 0 to 20 begin if(count == 8'd20) count <= 0 ; else count <= count +1; end else if(switch == 0 && button == 1) // Countdown from 20 to 0 begin if(count == 8'd0) count <= 8'd20 ; else count <= count -1; end else count <=8'd0; end endmodule module mux(A,B,sel,Y); // 2x1 Multiplexer input [3:0]A; input [3:0]B; input sel; output [3:0]Y; reg [3:0]Y; always @(*) begin if(sel==0) Y=A; else Y=B; end endmodule module hex7seg(input wire [3:0]x , output reg[6:0]a_to_g); // Hex to 7seg Code always @(*) case(x) 0: a_to_g = 7'b0000001; 1: a_to_g = 7'b1001111; 2: a_to_g = 7'b0010010; 3: a_to_g = 7'b0000110; 4: a_to_g = 7'b1001100; 5: a_to_g = 7'b0100100; 6: a_to_g = 7'b0100000; 7: a_to_g = 7'b0001111; 8: a_to_g = 7'b0000000; 9: a_to_g = 7'b0000100; 'hA: a_to_g = 7'b0001000; 'hB: a_to_g = 7'b1100000; 'hC: a_to_g = 7'b0110001; 'hD: a_to_g = 7'b1000010; 'hE: a_to_g = 7'b0110000; 'hF: a_to_g = 7'b0111000; default: a_to_g = 7'b0000001; endcase endmodule module segment (a,b,fast,enable,seg7); input [3:0]a; input [3:0]b; input fast; output [3:0] enable; output [6:0] seg7; wire [3:0]e1 = 4'b1110; wire [3:0]e2 = 4'b1101; wire slow; wire [3:0]number; clock c1(fast,slow); mux m1(a,b,slow,number); mux m2(e1,e2,slow,enable); hex7seg h1(number,seg7); endmodule |
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Edited by Moderator
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Basim Sheikh wrote: > it is giving me an error in active HDL > can you please tell me what is the error Can you please tell the ERROR MESSAGE and the corresponding line?
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Attached files:
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error.jpg
136 KB, 200 downloads -
erroe_e1.jpg
145 KB, 155 downloads
this picture is showing the error line and MESSAGE
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Edited by User
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Basim Sheikh wrote: > this picture is showing the error line and MESSAGE A syntax error is the most simple error that can occur. It shows up, when some character are not in the expected order. The compiler tells you, whats wrong. Correct it and try again. This extremely simple error here you must solve on your own. The necessary process is called: LEARNING! I'm the VHDL man, and I don't know Verilog. But it took me less than 1 minute and a Google search https://www.google.de/search?q=verilog+port+list to figure out whats leading to this error. Try this here:
segment s1(count[3:0],count[7:4],fastclk,enable,out); |
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