EmbDev.net

Forum: Analog Circuits Cutoff frequency for high/low pass filters


von Benny (Guest)


Attached files:

Rate this post
useful
not useful
Hey guys,

Could you shed a little light on this problem here? I'm trying to 
calculate the half power frequency for these 2 circuits, and I'm not 
sure if my reasoning/math is right:

For the former one, I did Fc=1/(2πR*C) where R=(R1*R2)/(R1+R2)+R3. Is 
this correct? Is this all?

How about the latter one?

Thank you

von Helmut S. (helmuts)


Rate this post
useful
not useful
Hello Benny,

You have to look from the capacitor into the circuit when you calculate 
the corner frequency or the time constant. Treat the voltage source as a 
short (0Ohm) for the calculation, because it has zero internal 
resistance.

a) Lowpass Filter

fc = 1/(2*pi*R*C)

R = 1/(1/R1 + 1/R2 + 1/R3)


b) Highpass Filter

fc = 1/(2*pi*R*C)

R = R1 + 1/(1/R2 + 1/R3)


By the way you can simulate this circuit with LTspice to check the 
results.

Best regards,
Helmut

von Benny (Guest)


Rate this post
useful
not useful
Thanks a lot Helmut

Please log in before posting. Registration is free and takes only a minute.
Existing account
Do you have a Google/GoogleMail account? No registration required!
Log in with Google account
No account? Register here.