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Forum: ARM programming with GCC/GNU tools Problems using char strings


Author: Vicente (Guest)
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Hello,

I'm using Eclipse with cygwin.

I have an app with a Timer 0 FIQ and a UART0 IRQ. The timer 0 is used to
simulate a PWM. In the UART ISR I have implemented a echo. I also have a
print(char *str) function. The problem is that the only way which the
program runs is declaring a string like that:

char str[100];

str[0]='q';
str[0]='w';
str[0]='e';
str[0]='r';
...

Print(str);

If I do this, everything works fine. But if I try to initialize the
string like this:
str = "qwert"
all interrups don't work anymore.

I have tried declaring:

const char *str;
const char *str = "qwerty";
Print("qwerty");
const char *str = {'q','w','e','r','t','y'};
...

and the conclusion I have at this moment is that if I use in my code the
character "" to indicate a string, it doesn't work.

Do you have any suggestion?
Thatk you very much.

Author: Jonathan Dumaresq (dumarjo)
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> const char *str;
> const char *str = "qwerty";
> Print("qwerty");
> const char *str = {'q','w','e','r','t','y'};
> ...
>

Hi,

I Ansi 'C' you should do this:

char str[] = "hello world";

you need to reserve the space in memory to store your string.

regards

Jonathan

Author: Clifford Slocombe (clifford)
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Vicente wrote:
> and the conclusion I have at this moment is that if I use in my code the
> character "" to indicate a string, it doesn't work.

In what way does it not work - fails to compile or runtime failure?
Describe the failure mode. Post the build log if it fails to build; post
complete example code rather than fragments in either case. Make sure
that you build with -Wall -Werror, compiler options, and clear up any
warnings.

Perhaps use of literal string constant where a constant is invalid? Hard
to tell from your post.

Clifford

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